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The serpent encipher suggestion in the Dais made me curious about how long it would take for someone to crack the cipher I made in zMUD. I posted about it before, years ago, but only one person responded at all and I don't think anyone actually tried.
So this time, whoever solves it first gets 5 credits. 10 credits if it's solved today.
Here are the ciphertext samples to crack. I won't say anything about the method used, except that it's a substitution cipher, and that there's a sort of complication added that makes the last sample a bit different than the rest.
,?ZRCeK'-l KCE'gW)*)966])p.]YjjwKM].-32wu-96ZD,MAV0heNu-7LNsg')*l_w2yL].KM$Z0=2]Yjjw26,?962ULbz22UwzZS6g.Og6Vo KM0
,t-0X2j8X2x7eNu-ZR].Rq96M1l_69j+:j*b].',].U..]V7].Rd'gAf-026,?96'KDZU2.]U2qZdQKMg'0N K-0AV2w4V].',XMS*'gJSE,Ce96W0$Z7L'g=t7L.]?7zwYjjwCE.]zn03ENyt'UX2j8g'VTT22U].2zgKl^'wu-96qZdQKM\MCe3*964VwC!eMb\MXEj?.JEN=t7L.]*)X.O2j8Ue]2J6Kr]6zjeNu..]Voajz22UXEKM?j2wMKQZVoE,ENty]6l_]674\MNEVo-.].Rd4!]6ofVo96l^b.=aaj].$Z,E26YV].Rd'g)*/UeNNk2TM,Mg?j3rK'CE.]VpKr.] K0-z9g9MKEG0-26s(g9MKEG0-CE2X*)k-g'jYM,ENLy*32t\2KM96l:96u-96qZdQKM.JLbg'SJZ=K'].2zgKl^'x\MwzVo-.g't*]6ofu-4V]w=t7L.]u-96/Uu-7AN.'KhW690+OE.]u-tyCE.-'g6]h00Q)*b.)*Vog9Gd',vK]674].-3.]u-KM9M'g6]?j:0z22X5jOiSZ^l)*Vo]6d_,E].-3.]JS'U'gu-96a=-0g'SJZ=966])p.]EGf_KMU2.]u-Fy].',gMK'bx